OKhttp深入理解--RetryAndFollowUpInterceptor
看看RetryAndFollowUpInterceptor的实现:
public Response intercept(Chain chain) throws IOException {
//...ignore code
int followUpCount = 0;
Response priorResponse = null;
//...开启循环
while (true) {
//...ignore code
Response response = null;
boolean releaseConnection = true;
try {
//执行下一个责任链,如果下一个责任链返回成功,就会跳出循环,否则重试。
response = ((RealInterceptorChain) chain).proceed(request, streamAllocation, null, null);
releaseConnection = false;
} catch (RouteException e) {
// The attempt to connect via a route failed. The request will not have been sent.
if (!recover(e.getLastConnectException(), false, request)) {
throw e.getLastConnectException();
}
releaseConnection = false;
continue;
} catch (IOException e) {
// An attempt to communicate with a server failed. The request may have been sent.
boolean requestSendStarted = !(e instanceof ConnectionShutdownException);
if (!recover(e, requestSendStarted, request)) throw e;
releaseConnection = false;
continue;
} finally {
// We're throwing an unchecked exception. Release any resources.
if (releaseConnection) {
streamAllocation.streamFailed(null);
streamAllocation.release();
}
}
// Attach the prior response if it exists. Such responses never have a body.
if (priorResponse != null) {
response = response.newBuilder()
.priorResponse(priorResponse.newBuilder()
.body(null)
.build())
.build();
}
//判断是否要重定向
Request followUp = followUpRequest(response);
if (followUp == null) {
if (!forWebSocket) {
streamAllocation.release();
}
return response;
}
closeQuietly(response.body());
//重定向的次数不能超过20
if (++followUpCount > MAX_FOLLOW_UPS) {
streamAllocation.release();
throw new ProtocolException("Too many follow-up requests: " + followUpCount);
}
if (followUp.body() instanceof UnrepeatableRequestBody) {
streamAllocation.release();
throw new HttpRetryException("Cannot retry streamed HTTP body", response.code());
}
if (!sameConnection(response, followUp.url())) {
streamAllocation.release();
streamAllocation = new StreamAllocation(
client.connectionPool(), createAddress(followUp.url()), callStackTrace);
} else if (streamAllocation.codec() != null) {
throw new IllegalStateException("Closing the body of " + response
+ " didn't close its backing stream. Bad interceptor?");
}
request = followUp;
priorResponse = response;
}
}
1.在执行下一个责任链的时候,如果有异常,它会调用recover来判断是否需要重新请求
2.如果followUp重定向成功,会重新创建Request去发请求
3.超时重试需要自己实现,OKHttp超时重试没做支持
4.身份认证失败的话可以走重新认证身份的逻辑
重点看followUpRequest
private Request followUpRequest(Response userResponse){
//...ignore code
int responseCode = userResponse.code();
final String method = userResponse.request().method();
switch (responseCode) {
case HTTP_PROXY_AUTH://407 代理服务器身份证异常
//...ignore code
return client.proxyAuthenticator().authenticate(route, userResponse);
case HTTP_UNAUTHORIZED://401 身份证异常
return client.authenticator().authenticate(route, userResponse);
case HTTP_PERM_REDIRECT://308
case HTTP_TEMP_REDIRECT://307
if (!method.equals("GET") && !method.equals("HEAD")) {
return null;
}
//...ignore code
}